2(r+1) = (3 - \sqrt{5})(r - 1)
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- r = rac{(5 + \sqrt{5})(1 - \sqrt{5})}{(1 + \sqrt{5})(1 - \sqrt{5})} = rac{5 - 5\sqrt{5} + \sqrt{5} - 5}{1 - 5} = rac{-4\sqrt{5}}{-4} = \sqrt{5}.
- Case 2:** \( rac{r+1}{r-1} = rac{3 - \sqrt{5}}{2} \)
- Similarly:
- 2r + 2 = (3 - \sqrt{5})r - (3 - \sqrt{5})
- 2r + 2 = (3 - \sqrt{5})r - 3 + \sqrt{5}
- 2r - (3 - \sqrt{5})r + 5 - \sqrt{5} = 0
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