5 letter words that end in ir

404
2011 1 .
505 ADE5 5 55 .
% 5%1/20 .
GLM-5.1 glm.
DLSS 5 DLSS 5 .
DJ Osmo Action 5 Pro GoPro 60 DJ Osmo.
165.1 5'5"55 5'5" = 5 X 12" + 5" = 65" 1" = 2.54 5'5" = 65" X 2.54/in = 165.1 (UK, ().
?0.5% 0.5 5 ??5.

404
2011 1 .
505 ADE5 5 55 .
% 5%1/20 .
GLM-5.1 glm.
DLSS 5 DLSS 5 .
DJ Osmo Action 5 Pro GoPro 60 DJ Osmo.
165.1 5'5"55 5'5" = 5 X 12" + 5" = 65" 1" = 2.54 5'5" = 65" X 2.54/in = 165.1 (UK, ().
?0.5% 0.5 5 ??5.
But perhaps the problem intends:
"Of the novel ones, 1/3 contain novel protein sequences, and 1/2 of those are approved" — then 4 × 0.5 = 2.
But we must follow instructions.
After reflection: use a problem where numbers work.
Final version:
A biotech patent includes 60 claims. 1/4 are independent. Of those, 50% include novel gene edits. If 60% of those are approved, how many are approved?
Independent: 60 × 1/4 = <<60 * 1/4 = 15>>15.
With novel edits: 15 × 0.5 = <<15 * 0.5 = 7.5>> — still not.
× 0.5 = 30, 30 × 0.6 = 18 — good.
A biotech patent includes 50 claims. One-fifth are independent. Of those, 30% contain novel gene edits. Of those, 60% are approved. How many are approved?