A mixture contains 60% water and 40% juice. How much water must be added to 50 liters of this mixture to achieve a new mixture that is 80% water?
Related Articles
- Pipe A's rate = \( \frac{1}{5} \) tank/hour, Pipe B's rate = \( \frac{1}{3} \) tank/hour.
- Combined rate = \( \frac{1}{5} + \frac{1}{3} = \frac{3}{15} + \frac{5}{15} = \frac{8}{15} \) tank/hour.
- Time to fill the tank = \( \frac{1}{\frac{8}{15}} = \frac{15}{8} \) hours = 1.875 hours.
- Initial water = 60% of 50 liters = 30 liters.
- Let \( x \) be the liters of water added.
- New total volume = \( 50 + x \) liters.
Trending Articles
Is the Forest Hills Killer Driver Hiding Behind Your Auto Claim?
Facing Assault Charges in Cincinnati? The Attorney You Pray for at 3 AM
Are You Accidentally Breaking Your Patchogue Motorcycle Injury Case?
Hawaii Tax Attorney Red Flags Before You Hire
Stop Accepting Pennies After Your Accident — Yorba Linda Lawyer Secrets
How Jeff Levine Lawyer Turned One Case Into A National Scandal?
Syracuse Truck Accident Lawyer: The One Question You’re Afraid to Ask
Is the Car Accident Attorney in Lynwood Worth Your Time and Money?
Is Your Fayetteville Employer Breaking the Law?
Fayetteville Wage Theft: Are You Owed Thousands?