A rectangle has a perimeter of 50 cm and a length that is 3 times its width. Find the dimensions of the rectangle.
["Discover the Step-by-Step Classical Solution to a Common Geometry Problem", "Want to know how to solve a classic shape puzzle that’s subtly shifting conversations online? A simple rectangle with a perimeter of 50 cm and a length three times its width offers both a mental exercise and real-world relevance. Whether you're preparing for a class project, exploring math basics, or curious about geometric relationships, solving this problem reveals core principles of geometry in everyday terms. It’s more than just numbers—it’s a gateway to understanding spatial reasoning and practical design.", "Why This Problem Is Quietly Gaining Momentum in the US", "Across educational platforms and lifestyle blogs, math problems tied to real-life shapes are emerging as accessible entry points into logic and problem-solving. The rectangle with perimeter 50 cm and length three times width reflects a growing interest in foundational STEM learning tailored for mobile-first users seeking both clarity and relevance. As curiosity sharpens around quick, applicable math, this question balances simplicity with subtle depth—stable enough for beginners, yet rich enough to spark thoughtful engagement.", "How to Find the Dimensions: A Clear Breakdown", "Start with the fundamental formula: Perimeter equals twice the sum of length and width. Given:", "- Perimeter = 50 cm \n- Length = 3 × Width", "Let width = \( w \), then length = \( 3w \). \nPlug into perimeter: \n\[\n50 = 2(w + 3w) = 2(4w) = 8w\n\] \nSolving for \( w \): \n\[\nw = \frac{50}{8} = 6.25 \ ext{ cm}\n\] \nLength = \( 3w = 3 \ imes 6.25 = 18.75 \ ext{ cm} \)", "This method demonstrates how algebraic substitution simplifies geometry—ideal for learners on mobile devices who value concise, visual problem paths.", "Common Questions About This Rectangle Puzzle", "H3: Why is this problem so popular in educational searches? \nIt combines a familiar shape with a straightforward equation, making it easy to"]
