\frac{(a + b)^2 + (a - b)^2}{(a - b)(a + b)} = 3
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- Solution: Let total articles be $ x $. $ 0.6x = 45 $. Divide: $ x = \frac{45}{0.6} = 75 $. \boxed{75}Question: If $\frac{a + b}{a - b} + \frac{a - b}{a + b} = 3$, find the value of $\frac{a^2 + b^2}{a^2 - b^2}$.
- \frac{a + b}{a - b} + \frac{a - b}{a + b} = 3
- Let’s combine the terms on the left-hand side:
- Expand the numerator:
- Adding them:
- The denominator is:
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