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Favorable cases: At least 2 gene-editing startups include (2 or 3).
Exactly 2: $ \binom{4}{2} \binom{2}{1} = 6 \cdot 2 = 12 $
Exactly 3: $ \binom{4}{3} = 4 $
Total favorable: $ 12 + 4 = 16 $.
Probability: $ \frac{16}{20} = \frac{4}{5} $.
Thus, the probability is $\boxed{\dfrac{4}{5}}$.Question:
Find the cubic polynomial \( f(x) \) such that \( f(1) = 3 \), \( f(2) = -1 \), \( f(3) = 2 \), and \( f(4) = 5 \).
To find the cubic polynomial \( f(x) = ax^3 + bx^2 + cx + d \), we use the given conditions to set up a system of equations:
\( f(1) = a(1)^3 + b(1)^2 + c(1) + d = 3 \), which simplifies to:
a + b + c + d = 3