Now solve for $z$:

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• 2x^2 - 3x + 1 = 0
• Solve the quadratic:
• x = \frac{3 \pm \sqrt{9 - 8}}{4} = \frac{3 \pm 1}{4} \Rightarrow x = 1, \frac{1}{2}
• $\sin z = 1 \Rightarrow z = 90^\circ$
• $\sin z = \frac{1}{2} \Rightarrow z = 30^\circ, 150^\circ$
• Thus, the solutions are:

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