\pi r \ell = \pi (5x)(13x) = 65\pi x^2.


We seek a subset of these values (from the sequence) that sum to 21, with each group size being a distinct Fibonacci number used at most once (because groups must be equal in size and we cant split monkeys).
But Fibonacci decomposition with distinct terms: try again.
Is there a combination with more than two groups using distinct Fibonacci numbers?
Wait: only distinct Fibonacci numbers can be used per group size, and each group has same size.
But can we use 5 + 3 + 2 + 1 + 1 + 1? No — invalid due to duplicates.
Wait — what about 5 + 3 + 2 + 1 = 11 — too small.
Is there a decomposition into more than two Fibonacci numbers with distinct values?
Thus, find largest number of groups (same size) such that group size divides 21 and is a Fibonacci number.
Are equal groups allowed to use Fibonacci number 3? Yes, if size 3 divides
Group size must be a Fibonacci number and divide 21.