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t = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} = \frac{5 \pm \sqrt{25 - 24}}{2} = \frac{5 \pm 1}{2}
Thus, \( t = 3 \) or \( t = 2 \). Since \( \sqrt{v} = t \), the roots \( v \) are \( v = 3^2 = 9 \) and \( v = 2^2 = 4 \). The product of the roots is:
\times 4 = 36
Hence, the product of the roots is \(\boxed{36}\).
Find all solutions to the inequality \( w^2 - 4w + 3 < 0 \).
First, solve the corresponding equation \( w^2 -
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