\(R = \frac{400 \times \sqrt{3}/2}{9.8} = \frac{200\sqrt{3}}{9.8}\).
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- The formula for range is \(R = \frac{v^2 \sin(2\theta)}{g}\).
- Substitute values: \(R = \frac{20^2 \sin(60°)}{9.8}\).
- \(\sin(60°) = \sqrt{3}/2\).
- Approximate: \(R \approx \frac{200 \times 1.732}{9.8} \approx 35.36 \, \text{m}\).
- #### Range: 35.36 m**Question:
- Compute the product of the roots of the equation \( v\sqrt{v} - 5v + 6\sqrt{v} = 0 \), given that all of the roots are real and positive.
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