So from the first condition: first + fifth = $2a = 14 \Rightarrow a = 7$
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- Second term + Fourth term: $(a - d) + (a + d) = 2a = 10$
- But this contradicts $2a = 14$. So letâs double-check the assumption.
- Actually, the second and fourth terms: $(a - d) + (a + d) = 2a = 10 \Rightarrow a = 5$
- Contradiction. So both cannot be true unless we made a mistake.
- Letâs re-express the sequence as:
- a, \, a + d, \, a + 2d, \, a + 3d, \, a + 4d
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