Solution: Factor the polynomial as $\frac{z^8 - 1}{z^2 - 1} = 0$ (excluding roots of $z^2 = 1$). The roots are the 8th roots of unity except $\pm 1$. The roots with maximum imaginary part are $e^{i\pi/4}$ and $e^{i3\pi/4}$, with imaginary part $\frac{\sqrt{2}}{2} = \cos(\pi/4)$.

February 22, 2026

$Solution: Factor the polynomial as $\frac{z^8 - 1}{z^2 - 1} = 0$ (excluding roots of $z^2 = 1$). The roots are the 8th roots of unity except $\pm 1$. The roots with maximum imaginary part are $e^{i\pi/4}$ and $e^{i3\pi/4}$, with imaginary part $\frac{\sqrt{2}}{2} = \cos(\pi/4)$.$

Solution: The given points lie on the base face of the cube in the $xy$-plane. The fourth vertex of the square face must complete the rectangle. The missing vertex is $(1,1,0)$, as it forms equal sides and right angles with the given points.
\boxed{(1,1,0)}
Question: For a polynomial modeling the trajectory of a seed dispersal algorithm, $z^6 + z^4 + z^2 + 1 = 0$, find the maximum imaginary part of a root expressed as $\cos \theta$, where $\theta$ is an acute angle.
\boxed{\cos\left(\frac{\pi}{4}\right)}
Question: Compute the sum of all angles $x \in [0^\circ, 360^\circ]$ satisfying $\sin(2x) = \frac{\sqrt{3}}{2}$, relevant to the symmetry of a linguistic phoneme cycle.
Solution: Solve $2x = 60^\circ, 120^\circ, 420^\circ, 480^\circ$ within $0^\circ \leq 2x \leq 720^\circ$. Thus, $x = 30^\circ, 60^\circ, 210^\circ, 240^\circ$. Sum: $30 + 60 + 210 + 240 = 540^\circ$.

Solution: Factor the polynomial as $\frac{z^8 - 1}{z^2 - 1} = 0$ (excluding roots of $z^2 = 1$). The roots are the 8th roots of unity except $\pm 1$. The roots with maximum imaginary part are $e^{i\pi/4}$ and $e^{i3\pi/4}$, with imaginary part $\frac{\sqrt{2}}{2} = \cos(\pi/4)$.

Related Articles

Trending Articles