The sum of the squares of three consecutive integers is 425. What is the smallest of these integers?
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- \[ 60 \times \frac{5280}{3600} = 60 \times \frac{22}{15} = 4 \times 22 = 88 \text{ ft/s} \]
- Acceleration \( a = \frac{\Delta v}{\Delta t} = \frac{88 \text{ ft/s}}{12 \text{s}} = \frac{88}{12} = \frac{22}{3} \approx 7.\overline{3} \) ft/s²
- #### 7.33
- Sum of squares:
- \[ (n-1)^2 + n^2 + (n+1)^2 = 425 \]
- \[ (n^2 - 2n + 1) + n^2 + (n^2 + 2n + 1) = 425 \]
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