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Here, \(P = 1000\), \(r = 0.05\), and \(n = 3\).
\(A = 1000 \times (1 + 0.05)^3 = 1000 \times 1.157625 = 1157.625\).
Solve for \(x\) in the equation \(3x^2 - 12x + 9 = 0\).
Factor the quadratic equation: \(3(x^2 - 4x + 3) = 0\).
Factor further: \(3(x - 3)(x - 1) = 0\).
Set each factor to zero: \(x - 3 = 0\) or \(x - 1 = 0\).
Solutions are \(x = 3\) or \(x = 1\).
#### 3, 1
A sequence is defined by \(a_n = 2n + 3\). What is the 10th term?
Substitute \(n = 10\) into the formula: \(a_{10} = 2(10) + 3 = 20 + 3 = 23\).